Complex-analytic implies holomorphic

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Revision as of 20:24, 14 April 2008 by Vipul (talk | contribs) (New page: ==Statement== Suppose <math>U \subset \mathbb{C}</math> is a domain and <math>f:U \to \mathbb{C}</math> is a complex-analytic function: for every point <math>z_0 \in U</math>, there e...)
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Statement

Suppose UC is a domain and f:UC is a complex-analytic function: for every point z0U, there exists a real number r>0 and a power series n=0an(zz0)n such that the power series converges and agrees with f in the ball of radius r.

Then, f is a holomorphic function: it is complex-differentiable, and the complex differential is a continuous function. In fact, f is differentiable infinitely often.

Proof

To execute this proof, we need to argue that