Complex-analytic implies holomorphic: Difference between revisions
(New page: ==Statement== Suppose <math>U \subset \mathbb{C}</math> is a domain and <math>f:U \to \mathbb{C}</math> is a complex-analytic function: for every point <math>z_0 \in U</math>, there e...) |
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==Proof== | ==Proof== | ||
We guess that the power series actually represents the ''Taylor expansion'' |
Revision as of 22:29, 14 April 2008
Statement
Suppose is a domain and is a complex-analytic function: for every point , there exists a real number and a power series such that the power series converges and agrees with in the ball of radius .
Then, is a holomorphic function: it is complex-differentiable, and the complex differential is a continuous function. In fact, is differentiable infinitely often.
Proof
We guess that the power series actually represents the Taylor expansion