Uniform limit of holomorphic functions is holomorphic: Difference between revisions
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* Since each <math>f_n</math> is holomorphic, it integrates to <math>0</math> along triangles, by Goursat's lemma. | * Since each <math>f_n</math> is holomorphic, it integrates to <math>0</math> along triangles, by Goursat's lemma. | ||
* Hence, <math>f</math> integrates to 0 along triangles, by uniform convergence on compact subsets, and the exchange of limit and integral. | * Hence, <math>f</math> integrates to 0 along triangles, by uniform convergence on compact subsets, and the exchange of limit and integral. | ||
* Hence, <math>f</math> is also | * Hence, <math>f</math> is also holomorphic, by [[Morera's theorem]]. | ||
The second assertion follows using the Cauchy integral formula for derivatives. This expresses the value of the derivative in temrs of an integral involving the function. {{fillin}} | The second assertion follows using the Cauchy integral formula for derivatives. This expresses the value of the derivative in temrs of an integral involving the function. {{fillin}} | ||
Revision as of 21:03, 27 April 2008
Statement
Suppose is a sequence of holomorphic functions on an open subset , and pointwise, with the convergence being uniform on compact subsets. Then is a holomorphic function, and moreover, for any , we have:
with this convergence also being uniform.
Facts used
Proof
The first assertion follows directly from Goursat's integral lemma and Morera's theorem.
- Since each is holomorphic, it integrates to along triangles, by Goursat's lemma.
- Hence, integrates to 0 along triangles, by uniform convergence on compact subsets, and the exchange of limit and integral.
- Hence, is also holomorphic, by Morera's theorem.
The second assertion follows using the Cauchy integral formula for derivatives. This expresses the value of the derivative in temrs of an integral involving the function. Fill this in later