Maximum modulus principle: Difference between revisions
No edit summary |
(→Proof) |
||
| Line 19: | Line 19: | ||
First, by the [[open mapping theorem]], <math>f</math> is an open map. | First, by the [[open mapping theorem]], <math>f</math> is an open map. | ||
Also, observe that the map <math>| \cdot |: \mathbb{C} \to [0,\infty)</math> is an open map. Thus, the composite map <math>|f|: U \to [0,\infty)</math> given by <math>z \mapsto |f(z)|</math> is also an open map. Thus, under this map, the image of <math>U</math> must be an open connected subset of <math>[0,\infty)</math> so it must be of the form <math>[0,a)</math> where <math>a \in \R</math> or <math>a = \infty</math>. Hence, there cannot be a maximum within <math>U</math>. | Also, observe that the [[modulus map]] <math>| \cdot |: \mathbb{C} \to [0,\infty)</math> is an open map. Thus, the composite map <math>|f|: U \to [0,\infty)</math> given by <math>z \mapsto |f(z)|</math> is also an open map. Thus, under this map, the image of <math>U</math> must be an open connected subset of <math>[0,\infty)</math> so it must be of the form <math>[0,a)</math> where <math>a \in \R</math> or <math>a = \infty</math>. Hence, there cannot be a maximum within <math>U</math>. | ||
Revision as of 19:24, 26 April 2008
This article gives the statement, and possibly proof, of a basic fact in complex analysis.
View a complete list of basic facts in complex analysis
This fact is an application of the following pivotal fact/result/idea: open mapping theorem
View other applications of open mapping theorem OR Read a survey article on applying open mapping theorem
Statement
Suppose is a domain (open connected subset). Let be a holomorphic function. The maximum modulus principle (sometimes called the maximum principle) states that if there exists a , such that for all , we have:
Then, is a constant function.
Facts used
Proof
Suppose is a nonconstant holomorphic function on a nonempty domain . We'll show that cannot have a maximum.
First, by the open mapping theorem, is an open map.
Also, observe that the modulus map is an open map. Thus, the composite map given by is also an open map. Thus, under this map, the image of must be an open connected subset of so it must be of the form where or . Hence, there cannot be a maximum within .