Cauchy-Riemann differential equations: Difference between revisions

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{{quotation|<math>u_x = v_y, \qquad u_y = -v_x</math>}}
{{quotation|<math>u_x = v_y, \qquad u_y = -v_x</math>}}


Note that if we are given that <math>u</math> and <math>v</math> are both continuously differentiable in the real sense, then satisfying the Cauchy-Riemann differential equations at <math>z_0</math> is equivalent to being complex-differentiable at <math>z_0</math>.
We can talk of a [[function satisfying Cauchy-Riemann differential equations at a point]].
Note that if we are given that <math>f</math> is differentiable at <math>z_0</math> in the real sense, then satisfying the Cauchy-Riemann differential equations at <math>z_0</math> is equivalent to being complex-differentiable at <math>z_0</math>. {proofat|[[Real-differentiable and Cauchy-Riemann equals complex-differentiable]]}}

Revision as of 00:49, 18 April 2008

Definition

Suppose U is an open subset of C and f:UC is a function. Write f in terms of its real and imaginary parts as follows:

f(z):=u(z)+iv(z)

We say that f satisfies the Cauchy-Riemann differential equations at a point z0U if the partial derivatives of the u,v in both the x and y directions exist, and satisfy the following conditions:

ux=vy,uy=vx

Using the subscript notation for partial derivatives, we can write this more compactly as:

ux=vy,uy=vx

We can talk of a function satisfying Cauchy-Riemann differential equations at a point. Note that if we are given that f is differentiable at z0 in the real sense, then satisfying the Cauchy-Riemann differential equations at z0 is equivalent to being complex-differentiable at z0. {proofat|Real-differentiable and Cauchy-Riemann equals complex-differentiable}}