Maximum modulus principle: Difference between revisions

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==Statement==
==Statement==


Suppose <math>U \subset \mathbb{C}</math> is a [[domain]] (open connected subset). Let <math>f:U \to \mathbb{C}</math> be a [[holomorphic function]]. The '''maximum principle''' states that if there exists a <math>z_0 \in U</math>, such that for all <math>z \in U</math>, we have:
Suppose <math>U \subset \mathbb{C}</math> is a [[domain]] (open connected subset). Let <math>f:U \to \mathbb{C}</math> be a [[holomorphic function]]. The '''maximum modulus principle''' (sometimes called the '''maximum principle''') states that if there exists a <math>z_0 \in U</math>, such that for all <math>z \in U</math>, we have:


<math>|f(z)| \le |f(z_0)|</math>
<math>|f(z)| \le |f(z_0)|</math>

Revision as of 13:53, 19 April 2008

Statement

Suppose UC is a domain (open connected subset). Let f:UC be a holomorphic function. The maximum modulus principle (sometimes called the maximum principle) states that if there exists a z0U, such that for all zU, we have:

|f(z)||f(z0)|

Then, f is a constant function.

Facts used

Proof

Suppose f is a nonconstant holomorphic function on a nonempty domain U. We'll show that f cannot have a maximum.

First, by the open mapping theorem, f is an open map.

Also, observe that the map ||:C[0,) is an open map. Thus, the composite map |f|:U[0,) given by z|f(z)| is also an open map. Thus, under this map, the image of U must be an open connected subset of [0,) so it must be of the form [0,a) where aR or a=. Hence, there cannot be a maximum within U.