Riemann mapping theorem: Difference between revisions
No edit summary |
m (6 revisions) |
||
(4 intermediate revisions by the same user not shown) | |||
Line 1: | Line 1: | ||
{{basic fact}} | |||
==Statement== | ==Statement== | ||
Any [[simply connected domain]] in <math>\mathbb{C}</math> (i.e. any open, connected and simply connected subset of <math>\mathbb{C}</math>) that is not the whole of <math>\mathbb{C}</math>, is [[biholomorphically equivalent domains|bihomolorphically equivalent]] to the open unit | Any [[simply connected domain]] in <math>\mathbb{C}</math> (i.e. any open, connected and simply connected subset of <math>\mathbb{C}</math>) that is not the whole of <math>\mathbb{C}</math>, is [[biholomorphically equivalent domains|bihomolorphically equivalent]] to the [[open unit disk]]. A biholomorphic mapping from the simply connected domain to the open unit disk is termed a [[Riemann mapping]]. | ||
==Corollaries== | ==Corollaries== | ||
Any two simply connected domains are homeomorphic (follows from the Riemann mapping theorem and the fact that the unit disc is homeomorphic to <math>\mathbb{C}</math>). | Any two simply connected domains are homeomorphic (follows from the Riemann mapping theorem and the fact that the unit disc is homeomorphic to <math>\mathbb{C}</math>). | ||
==Facts used== | |||
* [[Maximum modulus principle]] | |||
* [[Open mapping theorem]] | |||
==Proof== | |||
===Proof outline=== | |||
The standard proof of the Riemann mapping theorem has the following three steps: | |||
# Obtain a conformal mapping from the simply connected domain ''into'' the [[open unit disk]] (we do this by first obtaining a map into the upper half plane, and then using a [[fractional linear transformation]] to pass from the upper half plane to the open unit disk) | |||
# Maximize among all such mappings with respect to certain criteria. Prove that a maximal mapping must exist. | |||
# Prove that this maximal conformal mapping is also surjective, and hence, must be a biholomorphic mapping |
Latest revision as of 19:18, 18 May 2008
This article gives the statement, and possibly proof, of a basic fact in complex analysis.
View a complete list of basic facts in complex analysis
Statement
Any simply connected domain in (i.e. any open, connected and simply connected subset of ) that is not the whole of , is bihomolorphically equivalent to the open unit disk. A biholomorphic mapping from the simply connected domain to the open unit disk is termed a Riemann mapping.
Corollaries
Any two simply connected domains are homeomorphic (follows from the Riemann mapping theorem and the fact that the unit disc is homeomorphic to ).
Facts used
Proof
Proof outline
The standard proof of the Riemann mapping theorem has the following three steps:
- Obtain a conformal mapping from the simply connected domain into the open unit disk (we do this by first obtaining a map into the upper half plane, and then using a fractional linear transformation to pass from the upper half plane to the open unit disk)
- Maximize among all such mappings with respect to certain criteria. Prove that a maximal mapping must exist.
- Prove that this maximal conformal mapping is also surjective, and hence, must be a biholomorphic mapping