Dirichlet problem for a bounded domain: Difference between revisions
(New page: ==Definition== ===In Euclidean space=== Suppose <math>U \subset \mathbb{R}^n</math> is a bounded, connected open subset, and <math>f: \partial U \to \R</math> is a continuous function. T...) |
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* The restriction of <math>g</math> to <math>\partial U</math>is precisely <math>f</math> | * The restriction of <math>g</math> to <math>\partial U</math>is precisely <math>f</math> | ||
* The restriction of <math>g</math> to <math>U</math> is a [[harmonic function]] | * The restriction of <math>g</math> to <math>U</math> is a [[harmonic function]] | ||
Because harmonic functions satisfy a mean-valued property, a solution to the Dirichlet problem, if it exists, is unique. Moreover, the map sending a continuous function <math>f</math> that permits a solution, to the solution for it, is a linear operator. Solving the Dirichlet problem is often equated with finding an explicit form for the linear operator; for instance, in the form of an integral operator. | |||
===In the complex numbers=== | ===In the complex numbers=== | ||
A special case of the above, where <math>n = 2</math>, and we identify <math>\R^2</math> with <math>\mathbb{C}</math>. | A special case of the above, where <math>n = 2</math>, and we identify <math>\R^2</math> with <math>\mathbb{C}</math>. | ||
Latest revision as of 19:12, 18 May 2008
Definition
In Euclidean space
Suppose is a bounded, connected open subset, and is a continuous function. The Dirichlet problem for asks whether there exists a continuous function such that:
- The restriction of to is precisely
- The restriction of to is a harmonic function
Because harmonic functions satisfy a mean-valued property, a solution to the Dirichlet problem, if it exists, is unique. Moreover, the map sending a continuous function that permits a solution, to the solution for it, is a linear operator. Solving the Dirichlet problem is often equated with finding an explicit form for the linear operator; for instance, in the form of an integral operator.
In the complex numbers
A special case of the above, where , and we identify with .